Get all questions and answers of Complex Numbers of ICSE Class 11 Science Physics on TopperLearning. Diophantus of Alexandria (AD 210 – 294 approx) tried to solve the following problem. All the CBSE Worksheets for Class 11 Maths provided in this page are provided for free which can be downloaded by students, teachers as well as by parents. Ask a question on Maths and get answers by students, teacher and experts. शिक्षण कौशल (Teaching Skill) The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding. Scroll down to download HSSLIVE Class 11 Previous Question Paper of Maths with Answers. Complex Numbers and Quadratic Equations Chapter 5 Class 11 Maths NCERT Solutions were prepared according to CBSE marking scheme and … Exam Questions – Complex numbers. If you have any queries regarding CBSE Class 11 Maths Complex Numbers and Quadratic Equations MCQs Multiple Choice Questions with Answers, drop a comment below and we will get back to you soon. The NCERT Solutions for Chapter 5 Maths Class 11 is available in a free downloadable PDF version on Vedantu. Question 5.If ω is an imaginary cube root of unity, then (1 + ω – ω²)7 equals(a) 128 ω(b) -128 ω(c) 128 ω²(d) -128 ω², Answer: (d) -128 ω²Hint:Given ω is an imaginary cube root of unity.So 1 + ω + ω² = 0 and ω³ = 1Now, (1 + ω – ω²)7 = (-ω² – ω²)7⇒ (1 + ω – ω2)7 = (-2ω2)7⇒ (1 + ω – ω2)7 = -128 ω14⇒ (1 + ω – ω2)7 = -128 ω12 × ω2⇒ (1 + ω – ω2)7 = -128 (ω3)4 ω2⇒ (1 + ω – ω2)7 = -128 ω2, Question 6.The least value of n for which {(1 + i)/(1 – i)}n is real, is(a) 1(b) 2(c) 3(d) 4, Answer: (b) 2Hint:Given, {(1 + i)/(1 – i)}n= [{(1 + i) × (1 + i)}/{(1 – i) × (1 + i)}]n= [{(1 + i)²}/{(1 – i²)}]n= [(1 + i² + 2i)/{1 – (-1)}]n= [(1 – 1 + 2i)/{1 + 1}]n= [2i/2]n= inNow, in is real when n = 2 {since i2 = -1 }So, the least value of n is 2, Question 7.Let z be a complex number such that |z| = 4 and arg(z) = 5π/6, then z =(a) -2√3 + 2i(b) 2√3 + 2i(c) 2√3 – 2i(d) -√3 + i, Answer: (a) -2√3 + 2iHint:Let z = r(cos θ + i × sin θ)Then r = 4 and θ = 5π/6So, z = 4(cos 5π/6 + i × sin 5π/6)⇒ z = 4(-√3/2 + i/2)⇒ z = -2√3 + 2i, Question 8:The value of i-999 is(a) 1(b) -1(c) i(d) -i, Answer: (c) iHint:Given, i-999= 1/i999= 1/(i996 × i³)= 1/{(i4)249 × i3}= 1/{1249 × i3} {since i4 = 1}= 1/i3= i4/i3 {since i4 = 1}= iSo, i-999 = i, Question 9.Let z1 and z2 be two roots of the equation z² + az + b = 0, z being complex. Class 10 real numbers solutions. 2nd PUC Accountancy Question Bank with Answers Karnataka . All Solutions are updated for CBSE Exam 2021 based on new CBSE Curriculum 2021-2021 for CBSE Board, MP Board, Gujrat UP Board, Uttarakhand Board and Bihar Board, who are following NCERT Books 2020-21 for … 6) View Solution. Improve your Grades. 2. Need for complex numbers, especially √1, to be motivated by inability to solve some of the quardratic equations. Maths Important Questions Class 11 are given below. The chapter Complex Number and Quadratic Equation Class 11 consists of several mathematical concepts, theorems, and formulas that are fundamental for solving sums of algebra. CBSE papers with answers and solutions for chapter 05 Complex Numbers and Quadratic Equations class 11th Mathematics includes practice question papers with 10-12 questions in each test paper. Most of the chapters we will study in Class 11 forms a base of what we will study in Class 12. 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